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Hydrolysis of Salts

Chemistry ⇒ Acids, Bases, and Salts

Hydrolysis of Salts starts at 10 and continues till grade 12. QuestionsToday has an evolving set of questions to continuously challenge students so that their knowledge grows in Hydrolysis of Salts. How you perform is determined by your score and the time you take. When you play a quiz, your answers are evaluated in concept instead of actual words and definitions used.
See sample questions for grade 11
A 0.1 M solution of ammonium acetate is prepared. If K_a (acetic acid) = 1.8 × 10⁻⁵ and K_b (ammonia) = 1.8 × 10⁻⁵, what is the pH of the solution?
A solution contains 0.1 M sodium acetate. Calculate the concentration of OH⁻ ions. (K_a for acetic acid = 1.8 × 10⁻⁵, K_w = 1.0 × 10⁻¹⁴)
A solution of FeCl₃ is found to be acidic. Explain why.
Calculate the hydrolysis constant (K_h) for a 0.1 M solution of ammonium acetate (NH₄CH₃COO) if K_a (acetic acid) = 1.8 × 10⁻⁵ and K_b (ammonia) = 1.8 × 10⁻⁵. (K_w = 1.0 × 10⁻¹⁴)
Calculate the pH of a 0.1 M solution of sodium acetate (CH₃COONa). (Given: K_a for acetic acid = 1.8 × 10⁻⁵, K_w = 1.0 × 10⁻¹⁴)
Describe the effect of temperature on the degree of hydrolysis of salts.
Describe the process of hydrolysis for the salt ammonium acetate (NH₄CH₃COO).
Explain why the aqueous solution of ammonium chloride (NH₄Cl) is acidic.
Explain why the pH of a solution of potassium nitrate (KNO₃) is neutral.
Explain why the solution of sodium carbonate (Na₂CO₃) is basic.
Explain why the solution of sodium chloride does not undergo hydrolysis.
What is meant by the hydrolysis of a salt?
Write the hydrolysis reaction for the acetate ion (CH₃COO⁻) in water.
A 0.2 M solution of sodium cyanide (NaCN) is prepared. Given that the Ka of HCN is 4.9 × 10−10 and Kw is 1.0 × 10−14 at 25°C, calculate the pH of the solution.
A solution contains 0.05 M sodium benzoate (C6H5COONa). The Ka of benzoic acid is 6.3 × 10−5. Calculate the degree of hydrolysis (α) of the salt at 25°C. (Kw = 1.0 × 10−14)
Explain why the pH of a solution of ammonium formate (NH4HCOO) can be acidic, basic, or neutral depending on the values of Ka and Kb.
Explain, with equations, why the solution of aluminum chloride (AlCl3) in water is acidic.