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Hydrolysis of Salts

Chemistry ⇒ Acids, Bases, and Salts

Hydrolysis of Salts starts at 10 and continues till grade 12. QuestionsToday has an evolving set of questions to continuously challenge students so that their knowledge grows in Hydrolysis of Salts. How you perform is determined by your score and the time you take. When you play a quiz, your answers are evaluated in concept instead of actual words and definitions used.
See sample questions for grade 12
A 0.05 M solution of ammonium chloride (NH₄Cl) has a pH of 5.13. Is the solution acidic, basic, or neutral?
A 0.1 M solution of ammonium acetate (CH₃COONH₄) has Ka = 1.8 × 10⁻⁵ and Kb = 1.8 × 10⁻⁵. What is the pH of the solution?
A solution contains 0.1 M sodium acetate. Calculate the degree of hydrolysis if Ka = 1.8 × 10⁻⁵ and Kw = 1.0 × 10⁻¹⁴.
A solution contains 0.2 M sodium carbonate (Na₂CO₃). Will the solution be acidic, basic, or neutral?
A solution of FeCl₃ is found to be acidic. Explain why.
Calculate the degree of hydrolysis (h) for a 0.1 M solution of ammonium chloride (NH₄Cl). (Given: Kb for NH₃ = 1.8 × 10⁻⁵, Kw = 1.0 × 10⁻¹⁴)
Calculate the pH of a 0.1 M solution of sodium acetate (CH₃COONa). (Given: Ka for acetic acid = 1.8 × 10⁻⁵, Kw = 1.0 × 10⁻¹⁴)
Describe the process of hydrolysis for the salt ammonium acetate (CH₃COONH₄).
Explain the difference between the hydrolysis of a salt of a weak acid and strong base and that of a weak base and strong acid.
Explain the effect of dilution on the degree of hydrolysis of a salt of a weak acid and strong base.
Explain why the aqueous solution of ammonium chloride (NH₄Cl) is acidic.
Explain why the pH of a solution of ammonium acetate (CH₃COONH₄) depends on the relative values of Ka and Kb.
Explain why the solution of sodium chloride (NaCl) is neutral.
Explain why the solution of sodium cyanide (NaCN) is basic.
What is meant by the hydrolysis of a salt?
A 0.05 M solution of aniline hydrochloride (C6H5NH3Cl) is prepared. Given Kb for aniline = 4.0 × 10−10 and Kw = 1.0 × 10−14, calculate the pH of the solution.
A 0.2 M solution of sodium benzoate (C₆H₅COONa) is prepared. Given that the acid dissociation constant (Ka) for benzoic acid is 6.3 × 10−5 and Kw = 1.0 × 10−14, calculate the pH of the solution.
Explain why the degree of hydrolysis of a salt of a weak acid and a strong base is independent of the concentration of the salt, but the degree of hydrolysis of a salt of a weak acid and a weak base depends on the concentration.
Explain, with equations, why the aqueous solution of aluminum sulfate (Al2(SO4)3) is acidic.
For the salt sodium carbonate (Na2CO3), write the hydrolysis reaction and derive the expression for its hydrolysis constant (Kh) in terms of Kw and Ka of carbonic acid.