Born-Haber Cycle

Chemistry ⇒ Thermochemistry and Energetics

Born-Haber Cycle starts at 12 and continues till grade 12. QuestionsToday has an evolving set of questions to continuously challenge students so that their knowledge grows in Born-Haber Cycle. How you perform is determined by your score and the time you take. When you play a quiz, your answers are evaluated in concept instead of actual words and definitions used.

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Calculate the lattice enthalpy of NaCl given the following data (all values in kJ/mol): Enthalpy of formation = -411, Sublimation of Na = +108, Ionization energy of Na = +496, Bond dissociation energy of Cl_{2} = +242\), Electron affinity of Cl = -349. (Assume bond dissociation energy is for 1 mole of Cl_{2}.)

Describe the difference between lattice enthalpy and enthalpy of formation.

Describe the role of electron affinity in the Born-Haber cycle.

Describe the significance of the Born-Haber cycle in understanding the formation of ionic compounds.

Explain why the Born-Haber cycle for Al_{2}O_{3} includes three ionization energies for aluminum.

Explain why the lattice enthalpy of CaO is much higher than that of KCl.

Explain why the lattice enthalpy of LiF is higher than that of CsI.

Explain why the lattice enthalpy of MgO is higher than that of NaCl.

Explain why the second electron affinity of oxygen is positive.

Given the following data for the formation of CaCl_{2} (all in kJ/mol): Enthalpy of formation = -795, Sublimation of Ca = +178, First ionization energy of Ca = +590, Second ionization energy of Ca = +1145, Bond dissociation energy of Cl_{2} = +242, Electron affinity of Cl = -349. Calculate the lattice enthalpy of CaCl_{2}.

Given the following data for the formation of KCl (all in kJ/mol): Enthalpy of formation = -437, Sublimation of K = +89, Ionization energy of K = +419, Bond dissociation energy of Cl_{2} = +243, Electron affinity of Cl = -349. Calculate the lattice enthalpy of KCl.

Given the following data for the formation of MgO (all in kJ/mol): Enthalpy of formation = -602, Sublimation of Mg = +150, First ionization energy of Mg = +738, Second ionization energy of Mg = +1451, Bond dissociation energy of O_{2} = +498, First electron affinity of O = -141, Second electron affinity of O = +744. Calculate the lattice enthalpy of MgO.

In the Born-Haber cycle, why is the bond dissociation energy of Cl_{2} divided by 2 when calculating for NaCl?

List the main steps involved in constructing a Born-Haber cycle for the formation of an ionic compound from its elements.

The Born-Haber cycle is based on which fundamental law of thermochemistry?

What is the Born-Haber cycle used to calculate?

A compound AB_{2} is formed from elements A and B. The following enthalpy changes are given (in kJ/mol): - Enthalpy of formation of AB_{2} = -800 - Sublimation of A = +120 - First ionization energy of A = +500 - Second ionization energy of A = +900 - Bond dissociation energy of B_{2} = +200 - Electron affinity of B = -300 Calculate the lattice enthalpy of AB_{2}.

A student is given the following data for the formation of SrF_{2} (all values in kJ/mol): - Enthalpy of formation of SrF_{2} = -1215 - Sublimation enthalpy of Sr = +164 - First ionization energy of Sr = +549 - Second ionization energy of Sr = +1064 - Bond dissociation energy of F_{2} = +158 - Electron affinity of F = -328 Calculate the lattice enthalpy of SrF_{2}.

Discuss how the Born-Haber cycle can be used to estimate the covalent character in an ionic compound.

Explain why the Born-Haber cycle for the formation of MgCl_{2} requires two electron affinity steps for chlorine, but only one for magnesium.