subject

Absolute Value Equations and Inequalities

Math ⇒ Algebra

Absolute Value Equations and Inequalities starts at 9 and continues till grade 12. QuestionsToday has an evolving set of questions to continuously challenge students so that their knowledge grows in Absolute Value Equations and Inequalities. How you perform is determined by your score and the time you take. When you play a quiz, your answers are evaluated in concept instead of actual words and definitions used.
See sample questions for grade 12
Describe the difference between the solution sets of |x| < a and |x| > a, where a > 0.
Describe the steps to solve an absolute value equation of the form |ax + b| = c, where c > 0.
Explain why the equation |x + 1| = |x - 1| has two solutions.
Explain why the inequality |x| < -2 has no solution.
If |x - 1| + 2 = 7, what is the value of x?
If |x - 4| = 2x, what are the possible values of x?
If |x + 3| = 2x, find all real solutions for x.
If |x| < 2, what is the interval notation for the solution set?
Which of the following is always true for any real number x? (1) |x| ≥ 0 (2) |x| ≤ 0 (3) |x| = x (4) |x| < 0
Which of the following is the correct definition of absolute value? (1) The distance from x to 0 on the number line (2) The square of x (3) The reciprocal of x (4) The negative of x
Which of the following is the graph of the solution to |x| ≤ 5? (1) All real numbers (2) x < -5 or x > 5 (3) -5 ≤ x ≤ 5 (4) x = 5
Which of the following is the solution set for |2x + 1| = 5? (1) x = 2, x = -3 (2) x = 3, x = -2 (3) x = 2, x = -2 (4) x = 3, x = -3
Fill in the blank: The solution to |2x + 3| > 7 is x < ______ or x > ______.
Fill in the blank: The solution to |x - 7| ≤ 3 is _________.
Fill in the blank: The solution to |x + 4| ≤ 1 is _________.
Fill in the blank: The solution to |x + 5| = 0 is x = _______.
True or False: The equation |x| = 0 has exactly one solution.
True or False: The equation |x| = -4 has no real solution.
True or False: The solution to |x - 2| ≥ 0 is all real numbers.
True or False: The solution to |x + 2| = -1 is x = -3.